MnSO₄ - 4H₂O, thanksZinc sulfate is 40% zinc by weight.
Is the manganese sulfate hydrated?
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MnSO₄ - 4H₂O, thanksZinc sulfate is 40% zinc by weight.
Is the manganese sulfate hydrated?
MnSO₄ - 4H₂O, thanks
Thank you Randy, you are geniusFor the zinc sulfate, dissolve 1 gram of the solid material in 1 L of RO/DI. That solution contains 400 mg of zinc, so the concentration is 400 mg/L or 400 ug/mL.
Adding 1 mL to 400 L of tank water will boost aquarium zinc levels by 400 ug per 100 L or 4 ug/L.
There are just a few things you need to know to calculate stuff. I made a table to make this clear for myself.Hi Randy,
Yes, I do have some scales capable to do 0.01 gr and up, so should be ok)
Thank you, I made the same calculations but wanted to make sure that the powder I bought has this concentration as even the supplier couldn't give me proper answer.
Is there a formula for manganese sulfate?Yes.
Is there a formula for manganese sulfate?
I found some nickel sulfate. But the handling and storage of nickel and sodium fluoride is steering me away from DIYing these 2. Not wanting to buy a bomb suit lol. Any alternatives?Unless you are very into experimentation, I wouldn't boost nickel in a reef tank. Triton can only just barely detect the natural level, so none detected does not prove a big deficiency, and I'm not sure it has a beneficial role in reef tanks anyway. It can be toxic if overdosed.
Thanks for posting these, RHF. I'm off to the store today to pick up some iron and manganese per your chemistry archive mixing instructions.Manganese(II) chloride tetrahydrate is 28% manganese by weight.
Here's a recipe:
Dissolve 1 gram in 100o mL (grams) fresh water. Manganese = 280 ppm.
Take 1 mL (1 g) of that mix and dissolve in 1000 mL of fresh water. Mn = 0.28 ppm (=280 ug/L).
Add 1 mL of that to 100 mL of fresh water. Mn = 2.8 ug/L
Add 13.5 mL of that to 100 gallons of tank water. Conc boost to tank = 0.1 ug/L Mn.
MnSO₄ - 4H₂O, thanks
That product is 25% manganese by weight.
Dissolve 1 gram of the solid material in 1 L of RO/DI. That solution contains 250 mg of manganese, so the concentration is 250 mg/L or 250 ug/mL.
Adding 1 mL to 250 L of tank water will boost aquarium manganese levels by 250 ug per 250 L or 1 ug/L.
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Can I use the manganese sulfate monohydrated? The math is the same?
Thanks
Thanks for posting these, RHF. I'm off to the store today to pick up some iron and manganese per your chemistry archive mixing instructions.
For the Mn, can we stop at the second to last step to create a more concentrated stock with a goal to dose less daily volume? Stopping at 1.35 mL to 100 gallons of tank water to provide a 0.1 ug/L at the Mn = 2.8 ug/L step, or is there solubility issue or another reason to dilute it further?
Thank you
Same thing, working backwards x=(.02 mg/l *1,000,000 ml)/(2.5 ml) gives the 1L stock solution a 8000 ppm. but when then I try to adjust for a 225 gallon tank (~852L) I can seem to get your value. Based on the equation above I need 21.30 ml to dose however (8000 mg/l *21.3 ml) = (x * 852,000). x= (8000 mg/l * 21.30 ml)/(852,000 ml) gives me a ppm of 0.2. Am I doing something wrong?Potassium iodide is 77% iodine by weight.
If you target 0.02 ppm to dose, then you will want to add 0.02 mg iodide per liter of aquarium water.
That means dosing 0.025 mg of the KI per liter or 2.5 mg/100 L of aquarium water.
You won't likely be able to weight that small of an amount, so make a stock dosing solution.
Dissolve 1 g KI in 1 L RO/DI. That solution contains 1 mg KI per mL.
So 2.5 mL of that solution added per 100 L of aquarium water will boost iodine by 0.02 ppm.
I think you can dose this at least a couple of times a week in a typical tank.
That all said, I'm also not of the opinion that iodine dosing is useful for most reef tanks.